A square of side 3cm is located at a distance 25 cm from a concave mirror of focal length 10cm. The centre of square is at the axis of the mirror and the plane is normal to axis of mirror. The area enclosed by the image of the square is:

4 c m^{2}

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6 c m^{2}

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16 c m^{2}

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36 c m^{2}

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Solution

The correct option is A $4 c m^{2}$
Linear magnification
$m = \frac{I}{O} = \frac{f}{f - u} \Rightarrow m = \frac{- 10}{15} = \frac{- 2}{3}$
Axial magnification $= m^{2} = \frac{4}{9}$
Area of image $= \frac{4}{9}$ (area of object)
$= \frac{4}{9} \times (3)^{2} = 4 c m^{2}$

Suggest Corrections

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A square of side 3cm is placed at a distance of 25cm from a concave mirror

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