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Question
A steel rod of length 1 m is heated from 25∘C to 75∘C keeping its length constant. The longitudinal strain developed in the rod is (Given: Coefficient of linear expansion of steel =12×10−6/∘C) n×10−4 . Report n.
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Solution
Strain developed:
∈=αΔT=(12×10−6)(50)=6×10−4
Strain will be negative, as the rod is in a compressed state. Why this question?
Strain without changing length- yes that happens!
∈=αΔT=(12×10−6)(50)=6×10−4
Strain will be negative, as the rod is in a compressed state.
| Why this question? Strain without changing length- yes that happens! |
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