A stone is dropped freely from the top of a tower and it reaches the ground in $4 s$ . Taking $g = 10 m s^{- 2}$ , calculate the height of the tower.

80 m

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40 m

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4 m

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20 m

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Solution

The correct option is A 80 m
$S = u t + \frac{1}{2} g t^{2}$
as $u = 0$
So, $S = \frac{1}{2} g t^{2} = \frac{1}{2} \times 10 \times 4^{2} = 80 m$

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