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Byju's Answer
Standard XII
Physics
Relative Position
A stone is dr...
Question
A stone is dropped freely from the top of a tower and it reaches the ground in 4 sec taking (g =
10
m
s
2
). Calculate the height of the Tower.
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Solution
Given,
a
=
g
=
10
m
/
s
2
t
=
4
s
u
=
0
m
/
s
{Initial velocity at rest}
So, height=
u
t
+
1
2
a
t
2
=
(
0
)
(
u
)
+
1
2
(
10
)
(
16
)
=
80
m
∴
Height of the tower=
80
m
.
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