A stone is projected horizontally with speed $10m/s$ from a height $h$ above the ground. A horizontal wind is blowing in the direction opposite to the velocity of projection and gives the stone a constant horizontal acceleration $10m/s^2$ (in the direction opposite to the initial velocity). As a result the stone falls on ground at a point vertically below the point of projection. Then the value of height $h$ is ($g=10m/s^2$)

Q. A particle is projected downwards from point 'A' with initial velocity $5m/s$ at an angle $\theta ={37}^{o}C$ with the vertical. A strong horizontal wind gives the particle a constant horizontal acceleration of $6m/s^2$ in the x - direction. If the particle strikes the ground directly under its released position, the height 'h' of point A (in $m$) is (answer upto two decimal places). The downward acceleration is taken as $g=10m/s^2$ , take (sin37°=3/5, cos37°=4/5)

Q. A small platform starts moving from rest from ground in upward direction with uniform acceleration $5m{s}^{-2}$. At time $t=2s$, a stone is projected horizontally in frame of platform with speed $10m{s}^{-1}$. The maximum height attained by the stone with respect to the ground is (take $g=10m/s^2$)

Q. A stone is released at rest from a height of $45m$ above the horizontal level ground. There is horizontal wind blowing due to whcih stone acquires an additional (in addition to acceleration due to gravity) horizontal acceleration of magnitude $10m/s^2$. Then the net distance traveled by stone before reaching ground is: (Take $g=10m/s^2$ and neglect air resistance)

Q. From the top of a tower of height $78.4m$ two stones are projected horizontally with $10m/s$ and $20m/s$ in opposite directions. On reaching the ground, their separation is

Q. A stone is projected with a velocity $20\sqrt{2}m/s$ at an angle of ${45}^o$ to the horizontal. The average velocity of stone during its motion from starting point to its maximum height is: $(g=10m/s^2)$