A stone is projected vertically up from the top of a tower at a velocity 9.8 M per second it reaches the foot of the building in 4 seconds what is the height of the tower and velocity of the stone when it reaches the ground

Q. A body of mass $m$ is projected horizontally with a velocity $v$ from the top of a tower of height $h$ and it reaches the ground at a distance $x$ from the foot of the tower. If a second body of mass $2m$ is projected horizontally from the top of a tower of height $2h$, it reaches the ground at a distance $2x$ from the foot of the tower. The horizontal velocity of the second body is-

Q. A stone is projected up with a velocity of $4.9m/s$ from the top of a tower and it reaches the ground after 3 s. Then the height of that tower is

Q. A stone is thrown vertically up from the top of a tower with some initial velocity and it arrives on the ground after $t_1$ seconds. Now if the same stone is thrown vertically down from the top of the same tower with the same initial velocity, it arrives on ground after $t_2$ seconds. How much time will the stone take to reach the ground if it is dropped from the same tower ?