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Question

A tunnel is dug along the diameter of the earth. There is a particle of mass m at the centre of the tunnel. Find the minimum velocity given to the particle so that just reaches to the surface of the earth. (R=radius of earth)

A
GMR
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B
GM2R
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C
2GMR
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D
None of the above
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Solution

The correct option is A GMR
By conservation of energy,

Gain in K.E = Change in potential energy

12mv2=m[GMR[3GM2R]]

A gravitational potential at centre =32GMR

Gravitational potential at surface =GMR

Therefore,

12mv2=GMmR+32GMmR

=12mv2=GMm2R

v=GMR

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