A tunnel is dug in the earth across one of the diameter. Two masses m and 2m are dropped from two ends of tunnel. The masses collide and stick each other. They perform SHM amplitude of which is

Q. A tunnel is dug in the earth across one of its diameter. Two masses $m$ and $2m$ are dropped from the two ends of the tunnel. The masses collide and stick each other. They perform $SHM,$ the amplitude of which is $(R=$ radius of earth)

Q. A tunnel is dug n the earth across one of its diameter. Two masses 'm' & '2m' are dropped from the ends of the tunnel. The masses collide and stick to each other and performs S.H.M. Then amplitude of S.H.M. will be : [R=radius of the earth]

Q. A tunnel is dug in the earth across one of its diameters. Two masses $m$ and $2m$ are dropped from the ends of the tunnel. If the masses collide and stick to each other and perform $\text{S.H.M.}$ then amplitude of $\text{S.H.M.}$ will be: $(R=$ radius of the earth$)$

Q. A tunnel is dug along the diameter of the earth. Two balls of mass $m$ and $2m$ are dropped from the opposite ends of the tunnel simultaneously. They collide in the tunnel and stick to each other. If the new amplitude of their oscillation is $\frac{R}{n}$ where $R$ is earth's radius, then the value of $n$ is

Q. Two smooth tunnels are dug from one side of the earth's surface to the other side, one along with a diameter and the other along with a chord. Now two particles are dropped from one end of each of the tunnels. Both the particles oscillate simple harmonically along the tunnels. Let $T_1$ and $T_2$ be the time periods and $v_1$ and $v_2$ be the maximum speed of the particles in the two tunnels. Then :