A uniform chain of mass \(M\) and length \(L\) rests on a rough table such that one of its ends hangs over the edge. The chain starts sliding off the table by itself when overhanging part is equal to \(\dfrac{L}{4}\). The total work done by frictional force, till the moment the other end of chain slips-off the table, is
\( \Leftrightarrow M _{2} L \)