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Question

A uniform rod of mass M and length L is placed in a horizontal plane with one end hinged about the vertical axis. A horizontal force F=Mg2 is applied at a distance 5L6 from the hinged end. The angular acceleration of the rod will be


A

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B

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C

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D

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Solution

The correct option is B


τ=lα

α=τI=τFI=(5L6)(Mg2)ML23

α=5g4L


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