A uniform spring of force constant $k$ is cut into two pieces, the lengths of which are in the ratio $1:2$ .The ratio of the force constants of the shorter and the longer pieces is

Q. A spring of force constant $k$ is cut out into two pieces whose lengths are in the ratio $1:2.$ What is the force constant of the longer piece

Q. A spring of spring constant $k$ is cut into two pieces such that their lengths are in the ratio $1:2,$ then the force constant of the bigger piece will be

Q. A spring of force constant k is cut into lengths of ratio $1:2:3.$ They are connected in series and the new force constant is $k^{\prime }$. Then they are connected in parallel and force constant is $k^{\prime \prime }$. The ratio $k^{\prime }:k^{\prime \prime }$ is

Q. A spring of force constant $K$ is cut into lengths of ratio 1 : 2 : 3. They are connected in series and the new force constant is $K^{{}^{\prime }}$. Then, they are connected in parallel and the force constant is $K^{\prime \prime }$. Then, $\frac{K^{{}^{\prime }}}{K^{\prime \prime }}$ is

Q. The elongation of a spring of length $L$ and of negligible mass due to a force is $x$. The spring is cut into two pieces of lengths in ratio $1:n.$ The ratio of the respective spring constants is