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Question

A water treatment plant having flow rate of 600 m3/ hr has to remove 80% of the particles having a settling velocity of 0.18 cm/sec. The required plan area of a Type - I settling tank is

A
115.74 m2
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B
74.07 m2
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C
92.6 m2
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D
101.5 m2
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Solution

The correct option is B 74.07 m2
η=VsVo×100

80=0.18Vo×100

Vo=0.225 cm/s

[Vo=QPlan area]

A=600/36000.225×102=74.07 m2

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