According to the question an unbiased dice is thrown and the probability of getting an even no. And a multiple of 3 is 1/6... But zero is also a even and a multiple of 3 (proof: 2-2 is 0 and 3*0 is 0 respectively)... So answer should be 2/6 ie. 1/3... Please clear my doubt. 😃

Normally we don't take 0 in these case

In a single throw of an unbiased dice, you can get any one of the outcomes: 1, 2, 3, 4, 5, or 6.

So, exhaustive number of cases = 6.

(i) An even number is obtained if you obtain any one of 2, 4, 6 as an outcome.

So, favourable number of cases = 3.

Thus, required probability = 3/6 = 1/2

(ii) A multiple of 3 is obtained if you obtain any one of 3, 6 as an outcome.

So, favourable number of cases = 2

Thus, required probability = 2/6 = 1/3