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Atomic Number and Mass Number

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Question

According to the reaction above, what mass of oxygen gas is required to produce $88 g$ of carbon dioxide?
$C + O_{2} = C 0_{2}$

12 g

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16 g

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24 g

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64 g

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Solution

The correct option is D $64 g$
Molecular weight of Carbon Dioxide is 44 grams.
In each mole of Carbon dioxide, $16$ $$ $2$ $=$ $32$ grams of Oxygen is present.
44 grams of carbon dioxide contain 32 grams of Oxygen
1 grams of carbon dioxide contain $\frac{32}{44}$ grams of Oxygen
Thus, 88 grams of Carbon dioxide contain $\frac{32}{44}$ $$ $88$ grams of Oxygen, which is equal to 64 grams.
Thus Option E is the correct answer.

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According to the reaction above, what mass of oxygen gas is required to produce 88 g of carbon dioxide?C+O2=C02

According to the reaction above, what mass of oxygen gas is required to produce $88 g$ of carbon dioxide?
$C + O_{2} = C 0_{2}$