wiz-icon
MyQuestionIcon
MyQuestionIcon
147
You visited us 147 times! Enjoying our articles? Unlock Full Access!
Question

According to the reaction above, what mass of oxygen gas is required to produce 88 g of carbon dioxide?

C+O2=C02


A
12 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
16 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
24 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
64 g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 64 g
Molecular weight of Carbon Dioxide is 44 grams.
In each mole of Carbon dioxide, 16 2 = 32 grams of Oxygen is present.
44 grams of carbon dioxide contain 32 grams of Oxygen
1 grams of carbon dioxide contain 3244 grams of Oxygen
Thus, 88 grams of Carbon dioxide contain 3244 88 grams of Oxygen, which is equal to 64 grams.
Thus Option E is the correct answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Discovery of Subatomic Particles
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon