Alexandra wants to have eight triangular prism-shaped cakes for her birthday party. The base, height, and width of the cake is 12 in, 8 in, and 4 in, respectively. What should be the minimum volume of the box to hold eight pieces of cake?

1236 cu in

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1200 cu in

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1450 cu in

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1536 cu in

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Solution

The correct option is D 1536 cu in
Base of the cake = 12 in

Height of the cake = 8 in

Width of the cake = 4 in

$Volume of a cake$
$= \frac{1}{2}$ $\times$ Base $\times$ Height $\times$ Length

$= \frac{1}{2}$ $\times$ 12 $\times$ 8 $\times$ 4

= 192 sq in

For eight cakes,

Volume = 8 $\times$ 192

= 1,536 cu in

Hence, the minimum volume of the box required = 1,536 cu in

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Alexandra wants to have eight triangular prism-shaped cakes for her birthday party. The base, height, and width of the cake is 12 in, 8 in, and 4 in, respectively. What should be the minimum volume of the box to hold eight pieces of cake?

The correct option is D 1536 cu inBase of the cake = 12 in Height of the cake = 8 in Width of the cake = 4 in Volume of a cake =12× Base × Height × Length =12× 12 × 8 × 4 = 192 sq in For eight cakes, Volume = 8 × 192 = 1,536 cu in Hence, the minimum volume of the box required = 1,536 cu in