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Question

Although carbon and hydrogen are better reducing agents, they are not used to reduce metallic oxides at high temperatures. Why?

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Solution

At high temperature carbon and hydrogen react with metals to form carbides and hydrides respectively

Hence, carbon and hydrogen are not used to reduce metallic oxides at high temperatures

$C a O + 3 C \to C a C_{2} + C O$

$C a O + H_{2} \to C a H_{2} + C O$

Additional information:

Reduction of the metal oxide usually involves heating it with a reducing agent, for example C, or CO or H₂. The reducing agent (e.g., carbon) combines with the oxygen of the metal oxide.
$M_{x} O_{y} + y C \to x M + y C O$

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