Aluminium reacts with chlorine to produce

The correct option is D $AlC{l}_3$
Aluminum has three extra electrons in the outermost shell and will easily let the chlorine atoms use them. Each atom of chlorine is deficit of one electron. So each electron would be accepted by one other chlorine atom.
The reaction is,
$2Al+3C{l}_2\to 2AlC{l}_3$