Aluminum is extracted from alumina ( $A l_{2} O_{3}$ ) by electrolytes of a molten mixture of

A l_{2} O_{3} + H F + N a A l F_{4}

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A l_{2} O_{3} + C a F_{2} + N a A l F_{4}

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A l_{2} O_{3} + N a_{3} A l F_{6} + C a F_{2}

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A l_{2} O_{3} + K F + N a_{3} A l F_{6}

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Solution

The correct option is C $A l_{2} O_{3} + N a_{3} A l F_{6} + C a F_{2}$
Electrolytic mixture contains alumina $A l_{2} O_{3}$ , cryolite ( $N a_{3} A l F_{6}$ ) and flourspar ( $C a F_{3}$ ) in the ratio of $20 : 40 : 20$ . Due to the presence of these conductivity of alumina increases and fusion temperature decreases from $2000^{\circ} C$ to $900^{\circ} C$

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