An aeroplane is flying horizontally with a velocity of $600 k m / h$ and at a height of $1960 m$ . When it is vertically at a point $A$ on the ground a bomb is released from it. The bomb strikes the ground at point $B$ . The distance $A B$ is:

1200 m

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0.33 k m

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3.33 k m

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33 k m

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Solution

The correct option is C $3.33 k m$
The velocity with which the bomb is released is $600 k m / h (h o r i z o n t a l)$ .
Vertical velocity of the bomb is $z e r o$ .
So.distance $A B = 600 \frac{5}{18} * t$ $t$ is the time taken by the bomb to reach the ground.
$1960 = g \frac{t^{2}}{2}$
which gives $A B$ equal to $3.3. k m$ .

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