An aeroplane moving horizontally with a speed of 720 km/h drops a food pocket, while flying at a height of 396.9 m.the time taken by a food pocket to reach the ground and its horizontal range is (Take g = 9.8 m/ $s e c^{2}$ )

3 sec and 2000 m

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5 sec and 500 m

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8 sec and 1500 m

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9 sec and 1800 m

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Solution

The correct option is D
9 sec and 1800 m

t = $\sqrt{\frac{2 h}{g}}$ = $\sqrt{\frac{2 \times 396.9}{9.8}}$ $⋍$ 9sec and u = 720km/hr = 200m/s
$∴$ R = u $\times$ t = 200 $\times$ 9 = 1800m

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An aeroplane moving horizontally with a speed of 720 km/h drops a food pocket, while flying at a height of 396.9 m. the time taken by a food pocket to reach the ground and its horizontal range is (Take g = 9.8 m/ $s e c^{2}$ )

An airplane moving horizontally with a speed of 720 km/h drops a food pocket while flying at a height of 396.9 m. The time taken by a food pocket to reach the ground and its horizontal range is (Take g = 9.8 m/ $s e c^{2}$ )

Q. An aeroplane moving horizontally with a speed of

720 k m / h

drops a food packet, while flying at a height of

396.9 m

. The time taken by a food packet to reach the ground and its horizontal range is (Take

g = 9.8 m / {sec}^{2})

Q. An aeroplane moving horizontally with a speed of 720 km/h drops a food packet, while flying at a height of 396.9 m. The time taken by a food packet to reach the ground and its horizontal range is

(T a k e g = 9.8 m / s e c^{2})

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An aeroplane moving horizontally with a speed of 720 km/h drops a food pocket, while flying at a height of 396.9 m.the time taken by a food pocket to reach the ground and its horizontal range is (Take g = 9.8 m/sec2)

The correct option is D 9 sec and 1800 m t = √2hg=√2×396.99.8⋍9sec and u = 720km/hr = 200m/s ∴R = u ×t = 200×9 = 1800m

An aeroplane moving horizontally with a speed of 720 km/h drops a food pocket, while flying at a height of 396.9 m.the time taken by a food pocket to reach the ground and its horizontal range is (Take g = 9.8 m/ $s e c^{2}$ )

The correct option is D
9 sec and 1800 m

t = $\sqrt{\frac{2 h}{g}}$ = $\sqrt{\frac{2 \times 396.9}{9.8}}$ $⋍$ 9sec and u = 720km/hr = 200m/s
$∴$ R = u $\times$ t = 200 $\times$ 9 = 1800m