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Question

An alcohol A, when heated with concentrated H2SO4 gives an alkene B. When B is bubbled through bromine water and the product obtained is dehydrohalogenated with excess of sodamide, a new compound C is obtained. The compound C gives D when treated with warm dilute H2SO4 in presence of HgSO4. D can also be obtained either by oxidising A with KMnO4 or from acetic acid through its calcium salt. Identify D.

A
A = Ethylene, B = Ethyl alcohol,
C = Acetylene, D = Acetaldehyde
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B
A = Ethyl alcohol, B = Ethylene,
C = Acetylene, D = Acetaldehyde
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C
A = Ethylene, B = Ethyl alcohol,
C = Acetaldehyde, D = Acetylene
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D
A = Propan-2-ol, B = Propene,
C = Propyne, D = Acetone
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Solution

The correct option is D A = Propan-2-ol, B = Propene,
C = Propyne, D = Acetone
The facts given in the problem can be summarised as follows:

From the above it appears that C is an alkyne and D is an aldehyde or ketone. Since D can be obtained from acetic acid through its calcium salt it must be either acetaldehyde or acetone. Hence proceeding backwards A must be isopropyl alcohol.

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