An angle is ${14}^o$ more than its complement. Find its measure.

Two angle whose sum is ${90}^o$ are called complementary angels

Let one angle be $=x$

It's complementary angles $+x+14$

$x+x+14=90$

$2x=90-14$

$2x=76$

$x=\frac{76}{2}$

$x=38$

One angle is $38$

Second angle $=x+14$

$=38+14$

$52$

which is the requied answer.