An aqueous solution of an inorganic compound -X- -160-gives the following reactions-i- -160-With an aqueous solution of - BaCl-2- a precipitate -160-insoluble in dilute - HCl- -160-is obtained-ii- Addition of excess of - KI- gives a brown precipitate -160-which turns white on addition of excess hypo solution-iii- -160-With an aqueous solution of potassium ferrocyanide -160-a chocolate colored ppt- is obtained-Identify X - BaCl- CuSO-4- BaSO-4- NaI-

The correct option is B CuSO_4 Reaction Process:(i) CuSO_4+BaCl_2⟶ BaSO_4↓+2HCl (ii) #160; 2CuSO_4 amp;+ amp;4KI amp;⟶ amp;2K_2SO_4+CuI ...

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Byju's Answer

Standard XII

Chemistry

Stoichiometry

An aqueous so...

Question

An aqueous solution of an inorganic compound (X) gives the following reactions.

(i) With an aqueous solution of $B a C l_{2}$ , a precipitate insoluble in dilute $H C l$ is obtained.

(ii) Addition of excess of $K I$ gives a brown precipitate which turns white on addition of excess hypo solution.

(iii) With an aqueous solution of potassium ferrocyanide a chocolate colored ppt. is obtained.

Identify X :

C u S O_{4}

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B a S O_{4}

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B a C l

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N a I

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Solution

The correct option is B $C u S O_{4}$
Reaction Process:

(i) $C u S O_{4} + B a C l_{2} ⟶ B a S O_{4} ↓ + 2 H C l$
(ii) $\begin{matrix} 2 C u S O_{4} & + & 4 K I & ⟶ & 2 K_{2} S O_{4} + C u I_{2} ↓ & + & I_{2} ↓ W h i t e p p t . \end{matrix}$
(iii) $\begin{matrix} 2 C u^{2 +} & + & K_{4} [F e (C N)_{6}] & ⟶ & C u_{2} [F e (C N)_{6}] + 4 K^{+} R e d - b r o w n (c h o c o l a t e) p p t . \end{matrix}$

Therefore, from the above reaction, option A is correct.

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Similar questions

Q. An aqueous solution of inorganic compound

(X)

gives the following reactions.

(i) with an aqueous solution of

B a C l_{2}

a precipitate insoluble in dilute

H C l

is obtained.
(ii) addition of an excess of

K I

gives a brown appearance that turns white on the addition of an excess of hypo.
(iii) with an aqueous solution of

K_{4} F e (C N)_{6}

a chocolate coloured precipitate is obtained.

Identify

(X)

A black colored compound (A) on reaction with dilute

H_{2} S O_{4}

gives a gas (B) which on passing in a solution of acid (C) gives white turbidity (D). Gas (B) when placed in an acidified solution of a compound (E) gives a precipitate (F) soluble in dilute

H N O_{3} .

After boiling this solution, when an excess of

N H_{4} O H

is added, blue colored compound (G) is formed. To this solution on addition of

C H_{3} C O O H

and aqueous

K_{4} [F e (C N)_{6}]

, a chocolate precipitate (H) is obtained. On the addition of an aqueous solution of

B a C l_{2}

to an aqueous solution of E, a white ppt insoluble in

H N O_{3}

is obtained.

Identify B.

A black colored compound (A) on reaction with

d i l . H_{2} S O_{4}

gives a gas (B) which on passing in a solution of acid (C) gives white turbidity (D). Gas (B) when passed in an acidified solution of a compound (E) gives a black precipitate (F) which is soluble in hot concentrated (C). After boiling this solution when an excess of ammonia solution is added, a blue-colored compound (G) is formed. To the solution of (E), on the addition of acetic acid and aqueous potassium ferrocyanide, a chocolate brown precipitate (H) is formed. On the addition of an aqueous solution of

B a C l_{2}

to an aqueous solution of (E), white precipitate insoluble in

H N O_{3}

is obtained.

The gas (B) on passing through an acid (C) gives white turbidity (D) because :

Q. An aqueous solution of a gas

(X)

gives the following reactions :
(i) It turns an acidified

K_{2} C r_{2} O_{7}

solution green.
(ii) On boiling it with

H_{2} O_{2}

, cooling it and then adding an aqueous solution of

B a C l_{2}

, a precipitate insoluble in dilute hydrochloric acid is obtained.
(iii) On passing

H_{2} S

in the solution a white turbidity is obtained.
Identify (X).

Q. The aqueous solution of an inorganic compound (X) gives white precipitate with

N H_{4} O H

which does not dissolve in excess of

N H_{4} O H

This aqueous solution also gives white precipitate with

A g N O_{3}

and the precipitate is soluble in dilute

H N O_{3}

. Here, (X) is :

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The correct option is B CuSO4Reaction Process:(i) CuSO4+BaCl2⟶BaSO4↓+2HCl(ii) 2CuSO4+4KI⟶2K2SO4+CuI2↓+I2↓Whiteppt.(iii) 2Cu2++K4[Fe(CN)6]⟶Cu2[Fe(CN)6]+4K+Red−brown(chocolate)ppt.Therefore, from the above reaction, option A is correct.