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Question

An elevator car has a mass of 1600 kg and is carrying passengers having a combined mass of 200 kg. A constant friction force of 4000 N retards its motion. How much power must a motor deliver to lift the elevator car and its passengers at a constant speed of 3.00 m/s?
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Solution

F=Tfmg=0T=mg+f
p=Tv=Tv=(mg+f)v
p=(1800 kg)(9.8 m/s)+(4000 N)(3 m/sec)=6.49×104w
m=1800 kg
g=9.8
f=4000 N
v=3 m/sec

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