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Question
An elevator descends into a mine shaft at the of 6 Min/m . If the descent starts from 10m above the ground level, how long will it take to reach- 350m
An elevator descends into a mine shaft at the of 6 Min/m . If the descent starts from 10m above the ground level, how long will it take to reach- 350m
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Solution
Distance descended is denoted by a negative integer.
Initial height = +10 m
Final depth = −350 m
Total distance to be descended by the elevator = (−350) − (+10) = −360 m
Time taken by the elevator to descend −6 m = 1 min
Thus, time taken by the elevator to descend −360 m = (−360) ÷ (−6)
= 60 minutes = 1 hour
Distance descended is denoted by a negative integer.
Initial height = +10 m
Final depth = −350 m
Total distance to be descended by the elevator = (−350) − (+10) = −360 m
Time taken by the elevator to descend −6 m = 1 min
Thus, time taken by the elevator to descend −360 m = (−360) ÷ (−6)
= 60 minutes = 1 hour
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