An equilibrium mixture of $N_2,H_2$ and $N{H}_3$ at $700$K contains $0.036$M $N_2$ and $0.15$M $H_2$. At this temperature, $K_c$ for the reaction $N_2\left(g\right)+3H_2\left(g\right)\rightleftharpoons 2N{H}_3\left(g\right)$ is $0.29$. What is the concentration of $N{H}_3$?

Q. An equilibrium mixture of $N_2$, $H_2$, and $N{H}_3$ at $700K$contains $0.036M{N}_2$ and $0.15M$ $H_2$. At this temperature, $K_c$ for the reaction $N_2\left(g\right)+3H_2\left(g\right)\rightleftharpoons 2N{H}_3\left(g\right)$ is $0.29$. What is the concentration of $N{H}_3$?

Q. Assertion :For reaction $N_2\left(g\right)+3H_2\left(g\right)\rightleftharpoons 2{NH}_3\left(g\right)$ Unit of $K_C=L^2{mol}^{-2}$ Reason: For the reaction $N_2\left(g\right)+3H_2\left(g\right)\rightleftharpoons 2{NH}_3\left(g\right)$, Equilibrium constant $K_C=\frac{{\left[{NH}_3\right]}^2}{\left[N_2\right]{\left[H_2\right]}^3}$

Q. The following concentration were obtained for the formation of $N{H}_3$ form $N_2$ and $H_2$ at equilibrium for the reaction $N_2\left(g\right)+3H_2\left(g\right)\rightleftharpoons 2N{H}_3\left(g\right)$

$\left[N_2\right]=1.5\times {10}^{-2}M$
$\left[H_2\right]=3.0\times {10}^{-2}M$
$\left[N{H}_3\right]=1.2\times {10}^{-2}M$

Calculate equilibrium constant.

Q. At a certain temperature (T), the equilibrium constant $\left(K_c\right)$ is 1 for the reaction $N_2\left(g\right)+3H_2\left(g\right)\rightleftharpoons 2N{H}_3\left(g\right)$
If 2 moles of $N_2,$ 4 moles of $H_2,$ 6 moles of $N{H}_3$ and 3 moles of inert gas are introduced into a two litre rigid vessel at constant temperature T. It has been found that equilibrium concentration of $H_2$ and $N{H}_3$ are equal then what is the equilibrium concentration of $N_2$ (in M)?

Q. Calculate the equilibrium constant $\left(Kc\right)$ for the formation of $N{H}_3$ in the following reaction:
$N_2\left(g\right)+3H_2\left(g\right)\rightleftharpoons 2N{H}_3\left(g\right)$
At equilibrium, the concentration of $N{H}_3,H_2$ and $N_2$ are $1.2\times {10}^{-2},3.0\times {10}^{-2}$ and $1.5\times {10}^{-2}M$ respectively.