An international bank contains $2$ quarters, $3$ dimes, $4$ nickels, and $5$ pennies. One coin is removed at random. What is the probability that the coin is a quarter or a nickel?

\frac{1}{7}

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\frac{4}{3}

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\frac{2}{14}

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\frac{3}{7}

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Solution

The correct option is C $\frac{3}{7}$
Total number of coins $= 14$
Number of coin is a quarter or a nickel $= 2 + 4 = 6$
$P$ (coin is a quarter or a nickel) $=$ $\frac{N u m b e r o f q u a r t e r o r n i c k e l}{T o t a l n u m b e r o f c o i n s}$
$=$ $\frac{6}{14} = \frac{3}{7}$

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An international bank contains 2 quarters, 3 dimes, 4 nickels, and 5 pennies. One coin is removed at random. What is the probability that the coin is a quarter or a nickel?

The correct option is C 37Total number of coins =14Number of coin is a quarter or a nickel =2+4=6P (coin is a quarter or a nickel) = Number of quarter or nickelTotal number of coins= 614=37

An international bank contains $2$ quarters, $3$ dimes, $4$ nickels, and $5$ pennies. One coin is removed at random. What is the probability that the coin is a quarter or a nickel?

The correct option is C $\frac{3}{7}$
Total number of coins $= 14$
Number of coin is a quarter or a nickel $= 2 + 4 = 6$
$P$ (coin is a quarter or a nickel) $=$ $\frac{N u m b e r o f q u a r t e r o r n i c k e l}{T o t a l n u m b e r o f c o i n s}$
$=$ $\frac{6}{14} = \frac{3}{7}$