An object 1 cm-tall is placed 4 cm infront of a mirror- In order to produce an upright image of 3 cm-height one needs aPlane mirror of height 12 cmConcave mirror of radius of curvature 12 cmConvex mirror of radius of curvature 12 cmConcave mirror of radius of curvature 4 cm

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Image Formation in Concave Mirror

An object 1 c...

Question

An object 1 cm tall is placed 4 cm infront of a mirror. In order to produce an upright image of 3 cm height one needs a

Convex mirror of radius of curvature 12 cm

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Concave mirror of radius of curvature 12 cm

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Concave mirror of radius of curvature 4 cm

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Plane mirror of height 12 cm

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Solution

The correct option is B Concave mirror of radius of curvature 12 cm
Erect and enlarged image can produced by concave mirror.
$\frac{I}{O} = \frac{f}{f - u} \Rightarrow \frac{+ 3}{+ 1} = \frac{f}{f = (- 4)} \Rightarrow f = - 6 c m \Rightarrow R = 2 f = - 12 c m$

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An object 1 cm tall is placed 4 cm infront of a mirror. In order to produce an upright image of 3 cm height one needs a

The correct option is B Concave mirror of radius of curvature 12 cmErect and enlarged image can produced by concave mirror. IO=ff−u⇒+3+1=ff=(−4)⇒f=−6cm⇒R=2f=−12cm

The correct option is B Concave mirror of radius of curvature 12 cm
Erect and enlarged image can produced by concave mirror.
$\frac{I}{O} = \frac{f}{f - u} \Rightarrow \frac{+ 3}{+ 1} = \frac{f}{f = (- 4)} \Rightarrow f = - 6 c m \Rightarrow R = 2 f = - 12 c m$