An object 3 cm high is placed at a distance of 10 cm in front of a converging mirror of focal length 20 cm. Find the position, nature and size of the image formed.

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Solution

Given,
height of the object = 3cm
object distance = 10cm
focal length = 20cm
NOW,
According to Mirror formula,
1/f = 1/u + 1/v
1/v = -1/20 - (-1/10)
= -1/20 + 1/10
= (-1+2)/20
= 1/20
v = 20cm
NOW,
-v/u = h(I)/h(o)
-20/-10 = h(I)/ 3
h(I) = 2×3
h(I) = 6 cm

Nature:-Virtual

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An object 3 cm high is placed at a distance of 10 cm in front of a converging mirror of focal length 20 cm. Find the position, nature and size of the image formed.

Given, height of the object = 3cm object distance = 10cm focal length = 20cm NOW, According to Mirror formula, 1/f = 1/u + 1/v 1/v = -1/20 - (-1/10) = -1/20 + 1/10 = (-1+2)/20 = 1/20 v = 20cm NOW, -v/u = h(I)/h(o) -20/-10 = h(I)/ 3 h(I) = 2×3 h(I) = 6 cm Nature:-Virtual

Given,
height of the object = 3cm
object distance = 10cm
focal length = 20cm
NOW,
According to Mirror formula,
1/f = 1/u + 1/v
1/v = -1/20 - (-1/10)
= -1/20 + 1/10
= (-1+2)/20
= 1/20
v = 20cm
NOW,
-v/u = h(I)/h(o)
-20/-10 = h(I)/ 3
h(I) = 2×3
h(I) = 6 cm

Nature:-Virtual