An object of height 2cm is placed on the principal axis of a concave mirror at a distance of 12cm from the pole. If the image is real, inverted and 5cm high, then location of the image and the focal length of the mirror is
A
30cm,8.6cm
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B
30cm,7.6cm
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C
25cm,8.6cm
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D
25cm,7.6cm
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E
30cm,8.6cm
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F
30cm,7.6cm
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G
25cm,8.6cm
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H
25cm,7.6cm
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Solution
The correct option is A30cm,8.6cm Given:
Height of object, ho=+2cm
Height of image, hi=−5cm
Distance of object, u=−12cm
So, m=hiho=−vu ⇒−5+2=−v−12 ⇒v=−30cm
Applying mirror formula, 1v+1u=1f ⇒−130−112=1f ⇒1f=−760 ⇒f=−8.6cm