An object of mass 100 kg is accelerated uniformly from a velocity of 5m/s to 8 m/s in 6 s. Calculate the force acting on it.

1. Given data:

1. Mass of the object is $m=100kg$
2. Initial velocity is $u=5m/s$
3. Final velocity is $v=8m/s$
4. Time taken is $t=6s$.

2. Calculation of Force

1. Force can be calculated by using Newton's second law of motion.
2. Force is defined as the rate of change of momentum of a body.
3. Momentum can be calculated by using formula, $p=mv.$
4. $Force=\frac{Changeinmomentum}{Timetaken}=\frac{p_f-p_i}{t}$, where $p_f$ and $p_i$ are the final and initial momentum of the object respectively.
5. $Force=\frac{mv-mu}{t}=\frac{m(v-u)}{t}$
6. $F=\frac{100(8-5)}{6}=\frac{100\times 3}{6}=50N$

Hence, the force will be $50N$.