An object placed $3 m$ from a plane mirror is shifted further by $0.4 m$ away from the mirror. What is the new distance between the object and its image?

3.8 m

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6.6 m

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3.4 m

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6.8 m

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Solution

The correct option is D $6.8 m$
After shifting the object by $0.4 m$ ,Object distance from the mirror $= (3 + 0.4) = 3.4 m =$ Image distance

Distance between the object and its image $= (3.4 + 3.4) m = 6.8 m$

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An object placed 3 m from a plane mirror is shifted further by 0.4 m away from the mirror. What is the new distance between the object and its image?

The correct option is D 6.8 mAfter shifting the object by 0.4 m,Object distance from the mirror =(3+0.4)=3.4 m= Image distance Distance between the object and its image =(3.4+3.4) m=6.8 m

An object placed $3 m$ from a plane mirror is shifted further by $0.4 m$ away from the mirror. What is the new distance between the object and its image?

The correct option is D $6.8 m$
After shifting the object by $0.4 m$ ,Object distance from the mirror $= (3 + 0.4) = 3.4 m =$ Image distance

Distance between the object and its image $= (3.4 + 3.4) m = 6.8 m$