An organic compound contains carbon, hydrogen and oxygen. Its elemental analysis gave C,38.71%andH,9.67%. The empirical formula of the compound would be :
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Solution
element
% Composition
Atomic Mass
Molar Ratio
Simple Ratio
C
38.71
12
38.7112=3.22
3.223.22=1
H
9.67
1
9.671=9.67
9.673.22=3
O
100−(38.71+9.67)=51.62
16
51.6216=3.22
3.223.22=1
Thus the empirical formula of the compound is CH3O.