An unbiased die is thrown. What is the probability of getting:
an even number and a multiple of 3.

A unbiased die has $6$ possible values

$\{1,2,3,4,5,6\}$ In which

even numbers are

$2,4,6$

act of which multiple of $3$ is

"$6$"

total no. possible values of even number and multiple of $3$ is $1$

$\therefore \text{Probability}=\frac{1}{\text{total. no. of possible values}}$

$=\frac{1}{6}$