Arrange the following in ascending order of magnitude: $\sqrt[4]{490},\sqrt[3]{310},\sqrt{6}$

The correct option is A $\sqrt{3}<\sqrt[4]{410}<\sqrt[3]{36}$
$\sqrt[4]{410}=\sqrt[12]{121000}$
$\sqrt[3]{36}=\sqrt[12]{121296}$
$\sqrt{3^6}=\sqrt[12]{12729}$
$\sqrt[12]{121296}>\sqrt[12]{121000}>\sqrt[12]{12729}$

$\sqrt[3]{36}>\sqrt[4]{410}>\sqrt{3}$
or $\sqrt{3}<\sqrt[4]{410}<\sqrt[3]{36}$