Arrange the following oxides in the increasing order of basic character.
$M g O, S r O, K_{2} O, N i O, C s_{2} O$

K_{2} O < N i O < M g O < S r O < C s_{2} O

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N i O < S r O < K_{2} O < M g O < C s_{2} O

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N i O < M g O < S r O < K_{2} O < C s_{2} O

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N i O < K_{2} O < M g O < S r O < C s_{2} O

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Solution

The correct option is C $N i O < M g O < S r O < K_{2} O < C s_{2} O$
As the size of the metal increases, basic nature of metal oxides also increases. The size of metals in the increasing order is given below:
$N i < M g < S r < K < C s$
So, the increasing order of basic character is as follows:
$N i O < M g O < S r O < K_{2} O < C s_{2} O$
Hence, option C is correct.

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