Arrange the following species in order of increasing stability:$L{i}_2,L{i}_2^{+},L{i}_2{}^{-}$

The correct option is D $L{i}_2^{+}=L{i}_2{}^{-}<L{i}_2$
The correct order of stability is $L{i}_2^{+}=L{i}_2{}^{-}<L{i}_2$
$L{i}_2$ molecule has MO electronic configuration of $KK(2s{)}^2$. Its bond order is $\frac{N_b-N_a}{2}=\frac{2-0}{2}=2$
$L{i}_2^{+}$ molecule has MO electronic configuration of $KK(2s{)}^1$. Its bond order is $\frac{N_b-N_a}{2}=\frac{1-0}{2}=0.5$
$L{i}_2^{-}$ molecule has MO electronic configuration of $KK\left(2s{)}^2\right(2s^{\ast }{)}^1$. Its bond order is $\frac{N_b-N_a}{2}=\frac{2-1}{2}=0.5$
Higher is the bond order, higher is the stability.