Assertion :A particle has constant acceleration is x-y plane. But neither of its acceleration components $(a_{x}$ and $a_{y})$ is zero. Under this condition particle can not have parabolic path. Reason: In projectile motion, horizontal component of acceleration is zero.

Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Assertion is correct but Reason is incorrect

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Assertion is incorrect but Reason is correct

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D Assertion is incorrect but Reason is correct
Assertion is incorrect ,
assume $a_{x} = a s i n w t$ and $a_{y} = a c o s w t$ ,
we can show that x and y follows parabolic path .
Reason is correct ,
since in projectile motion horizontal velocity is constant therefore horizontal acceleration is zero.

Suggest Corrections

Similar questions

y = A sin (k x - ω t)

x = 0

y -

x -

H_{2}

H e

(1 + \frac{P b}{R T})

H_{2}

H e

{2n}^{2}

Assertion: All the points (1, 0), (-1, 0), (2, 0) and (5, 0) lie on the x – axis.
Reason: Equation of the x-axis is y = 0

Choose the correct option.

Join BYJU'S Learning Program