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Question
Assume that 2×10−17 J of light energy is needed by the interior of the human eye to see an object. How many photons of yellow light with λ=595.2 nm are needed to generate this minimum energy?
Assume that 2×10−17 J of light energy is needed by the interior of the human eye to see an object. How many photons of yellow light with λ=595.2 nm are needed to generate this minimum energy?
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Solution
The correct option is D 60
Enegy of a photon=hc/λ
Enegy of n number of photons =nhc/λ
E=nhcλ
By substituting:
E=2×10−17J
h=6.62×10−34J
c=3×108 ms−1
λ=595.2×10−9
we get n=60
Enegy of a photon=hc/λ
Enegy of n number of photons =nhc/λ
E=nhcλ
By substituting:
E=2×10−17J
h=6.62×10−34J
c=3×108 ms−1
λ=595.2×10−9
we get n=60
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