At a particular locus, frequency of ‘A’ allele is 0.6 & that of ‘a’ is 0.4. What would be the frequency of heterozygotes in a random mating population at equilibrium?

0.3

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0.16

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0.24

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0.48

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Solution

The correct option is D 0.48
Frequency of heterozygotes = 2pq

Here, p = 0.6, q = 0.4.

$∴$ Frequency of heterozygotes $= 2 \times 0.6 \times 0.4 = 0.48$

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