1
Question
At STP, 2 g of helium gas occupies a volume of t
Open in App
Solution
Assuming that helium behaves as an ideal gas, we know that a mole of ideal gas occupies 22.4 litres at STP.
The atomic weight of helium is 4 g/mol, so 2 g is 0.5 moles.
The volume occupied at STP, therefore, is
22.4 x 0.5 = 11.2 litres.
Assuming that helium behaves as an ideal gas, we know that a mole of ideal gas occupies 22.4 litres at STP.
The atomic weight of helium is 4 g/mol, so 2 g is 0.5 moles.
The volume occupied at STP, therefore, is
22.4 x 0.5 = 11.2 litres.
Suggest Corrections
0
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
