At $STP$ volume occupied by 11.2 grams of a gas of vapour density 11.2 in litres will be:

The correct option is C 11.2
11.2 g of gas has vapour density = 11.2

We know, Molar mass = 2 $\times$ Vapour density (VD)

Molar mass = 2 $\times$ 11.2 = 22.4 g/mol

No. of moles of gases = $\frac{11.2}{22.4}$ = 0.5 moles

1 mole of gas occupies 22.4 litres of volume

$\therefore$ 0.5 moles of gas will occupy 11.2 litres of volume