At the height $80$ m, an aeroplane is moving with $150$ $m s^{- 1}$ . A bomb is dropped from it, so as to hit a target. At what distance from the target should bomb be dropped? $(g = 10 m s^{- 2})$ .

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Solution

Given speed of aeroplane =150 m/s and height of the plane from the surface =80 m.
Now horizontal distance BC covered by the bomb = $v_{H} \times \sqrt{\frac{2 h}{g}}$
$150 \times \sqrt{\frac{2 \times 80}{10}} = 150 \times 4 = 600 m$
Now distance between the target and dropping point of the bomb $A C = \sqrt{{B C}^{2} + {A B}^{2}} = \sqrt{600^{2} + 80^{2}} = 605.3 m$

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At the height 80m, an aeroplane is moving with 150 ms−1. A bomb is dropped from it, so as to hit a target. At what distance from the target should bomb be dropped? (g=10ms−2).

Given speed of aeroplane =150 m/s and height of the plane from the surface =80 m. Now horizontal distance BC covered by the bomb =vH×√2hg150×√2×8010=150×4=600mNow distance between the target and dropping point of the bomb AC=√BC2+AB2=√6002+802=605.3m

At the height $80$ m, an aeroplane is moving with $150$ $m s^{- 1}$ . A bomb is dropped from it, so as to hit a target. At what distance from the target should bomb be dropped? $(g = 10 m s^{- 2})$ .