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Question

Box 1 contains three cards bearing numbers 1,2,3; box 2 contains five cards bearing numbers 1,2,3,4,5; and box 3 contains seven cards bearing numbers 1,2,3,4,5,6,7. A card is drawn from each of the boxes. Let xi be the number on the card drawn from the ith box, i=1,2,3.

The probability that x1+x2+x3 is odd, is

A
29105
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B
53105
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C
57105
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D
12
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Solution

The correct option is B 53105
Sum of x1+x2+x3 to be odd,
Case 1:
When all is odd
Probability =2×3×43×5×7=835

Case 2:
When one of them is odd,
When x1 is odd
Probability =2×2×33×5×7=435
When x2 is odd
Probability =1×3×33×5×7=335
When x3 is odd
Probability =1×2×43×5×7=8105
Therefore the required probability will be
=835+435+335+8105=53105

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