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Question

Box I contain three cards bearing numbers 1,2,3; box II contains five cards bearing numbers 1,2,3,4,5; and box III contains seven cards bearing numbers 1,2,3,4,5,6,7. A card is drawn from each of the boxes. Let xi be the number on the card drawn from the ith box i=1,2,3.

The probability that x1+x2+x3 is odd, is ?


A

29105

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B

53105

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C

57105

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D

12

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Solution

The correct option is B

53105


Probability=Number of favourable outcomesNumber of total outcomes
As, x1+x2+x3 is odd.
So, all may be odd or one of them is odd and other two are even.
Required probability
=2C1×3C1×4C1 + 2C1×2C1×3C1 + 1C1×3C1×3C1 + 1C1×2C1×4C13C1×5C1×7C1=24+12+9+8105=53105


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