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Question

By passing a certain amount of charge through NaCl solution, 9.2 litre of Cl2 were liberated at S.T.P. When the same charge is passed through a nitrate solution of metal M, 7.467 g of the metal was deposited. If the specific heat of metal is 0.216 cal/g, what is formula of metal nitrate ?


A

MNO3

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B

M(NO3)2

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C

M(NO3)3

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D

M(NO3)4

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Solution

The correct option is C

M(NO3)3



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