By using the formula, find the amount and compound interest on Rs. $6000$ for $2$ years at $9 %$ per annum compounded annually.

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Solution

$A = P {(1 + \frac{R}{100})}^{T}$
$\Rightarrow A = 6000 {(1 + \frac{9}{100})}^{2}$
$= 6000 \times {(\frac{109}{100})}^{2}$
= 7128.6 /-
$\Rightarrow$ Compound interest = A-P.
= 7128.6 - 6000
= 1128.6/-

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By using the formula, find the amount and compound interest on Rs. 6000 for 2 years at 9% per annum compounded annually.

A=P(1+R100)T⇒A=6000(1+9100)2=6000×(109100)2= 7128.6 /-⇒ Compound interest = A-P.= 7128.6 - 6000= 1128.6/-

By using the formula, find the amount and compound interest on Rs. $6000$ for $2$ years at $9 %$ per annum compounded annually.

$A = P {(1 + \frac{R}{100})}^{T}$
$\Rightarrow A = 6000 {(1 + \frac{9}{100})}^{2}$
$= 6000 \times {(\frac{109}{100})}^{2}$
= 7128.6 /-
$\Rightarrow$ Compound interest = A-P.
= 7128.6 - 6000
= 1128.6/-