Calculate the amount of water produced by the combustion of 16g of methane .

Dear student,

The balance combustion reaction of methane can be written as:

CH₄ + 2 O₂ ---> CO₂ + 2 H₂O

Given:

Mass of CH₄ = 16 g

Molar mass of CH₄ = 16 g/mol

Hence moles of CH₄ = 16 g / 16 g/mol = 1 moles

According to balance equation 1 mole of CH₄ is combusted to from 2 mole of H₂O ; hence moles ratio of CH₄ and H₂O produced must be 1 : 2.

Hence moles of H₂O formed = 2 x 1 moles = 2 moles

Molar mass of H₂O = 18.0 g/mol

Hence mass of H₂O produced = 2 moles x 18.0 g/mol = 36 g

Answer : 36 g of H₂O produced

Regards