Calculate the electric field strength required to just support a water drop of mass ${10}^{-7}kg$ having a charge $1.6\times {10}^{-19}C$.

Q. Calculate the electric field strength required to just support a water drop of mass ${10}^{-7}$ kg and having a charge $1.6\times {10}^{-19}C.$

Q. Calculate the electric field intensity required to just support a water drop let of mass ${10}^{-7}kg$ and having a charge of $+4.0\times {10}^{-13}C$.

Q. The electric field strength in $N{C}^{-1}$ that us required to just prevent a water drop carrying a charge $1.6\times {10}^{-19}$C from falling under gravity is: ($g=9.8m{s}^{-2}$, mass of water drop$=0.0016$g)

Q. The intensity of electric field required to balance a proton of mass $1.7\times {10}^{-27}kg$ and charge $1.6\times {10}^{-19}C$ is nearly.

Q. In a Millikan's oil drop method, a charged drop of oil has mass m and charge q. It is made stationary by applying an electric field E. Find the strength of the electric field. If the result of Millikans experiment with different drops is $6.48\times {10}^{-19}C,12.82\times {10}^{-19}C,19.3\times {10}^{-19}C,8.02\times {10}^{-19}C,25.62\times {10}^{-19}C,16.04\times {10}^{-19}C,$ find the elementary charge.