Calculate the ionic radius of a Cs⁺ ion assuming the cell edge length for CsCl is 0.4123 nm and that the ionic radius of a Cl^- ion is 0.181 nm.

Q. Calculate the ionic radius of a $C{s}^{+}$ ion assuming that the cell edge length for $CsCl$ is 0.4123 nm and that the ionic radius of a $C{l}^{-}$ ion is 0.181 nm.

Q. $CsCl$ has cubic structure of ions in which $C{s}^{+}$ ions is present in the body-centre of the cube. If density is $3.99gc{m}^{-3}$.
(a) Calculate the length of the edge of a unit cell.
(b) What is the distance between $C{s}^{+}$ and $C{l}^{-}$ ions?
(c) What is the radius of $C{s}^{+}$ ion if the radius of $C{l}^{-}$ ion is $180pm$?

Q. If the length of body diagonal for $\text{CsCl}$, which crystallises into a cubic structure with ${\text{Cl}}^{-}$ ions at the corners and ${\text{Cs}}^{+}$ ions at the centre of unit cell is $7\mathring{A}$ and the radius of ${\text{Cs}}^{+}$ ion is $1.69\mathring{A}$. The radius of ${\text{Cl}}^{-}$ ion?

Q. The unit cell cube length for $LiCl(NaCl$ structure) is $514\stackrel{\circ }{A}$. Assuming anion-anion contact, calculate the ionic radius for chloride ion.

Q. The unit cell cube length for $LiCl$ is $5.14\stackrel{o}{A}$. Assuming anion-cation contact, calculate the ionic radius for chloride ion.